Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 9 - Plug and Chug: 35

Answer

$$F= 2.1 \times 10^{20} N $$

Work Step by Step

$$F= G \frac{m_{1} m_{2}}{d^{2}} = (6.67 \times 10^{-11} \frac {N \cdot m^{2}}{kg^{2}}) \frac{(7.4 \times 10^{22} kg )(6.0 \times 10^{24} kg)}{(3.8 \times 10^{8} m)^{2}} $$
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