Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 7 - Think and Discuss - Page 130-131: 115

Answer

For the same change in speed, the KE would change more if the speed was higher to start with.

Work Step by Step

KE depends on the square of the speed. We see that $(30 \frac{km}{h})^{2} - (20 \frac{km}{h})^{2}$ is greater than $(20 \frac{km}{h})^{2} - (10 \frac{km}{h})^{2}$.
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