W = Fd = (500 N)(2.2 m) = $1100 N \cdot m = 1100 J$ This also the gain in PE.
Work Step by Step
W= Fd (500N)(2.2m) = 1100 Joules 1100 Joules is the gain of potential energy of the barbell when it is lifted to 2.2 meters off the floor.
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