Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 7 - Plug and Chug: 31


W = Fd = (500 N)(2.2 m) = $1100 N \cdot m = 1100 J$ This also the gain in PE.

Work Step by Step

W= Fd (500N)(2.2m) = 1100 Joules 1100 Joules is the gain of potential energy of the barbell when it is lifted to 2.2 meters off the floor.
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