## Conceptual Physics (12th Edition)

Use the conservation of momentum principle. The momentum before the collision equals the momentum after the collision. m1u1+m2u2=m1v1+m2v2 This implies: $$(40 kg)(0) + (15 kg)(3.0 m/s) = (40.0 kg + 15 kg) v$$ $$v = 0.8 m/s$$
$$(40 kg)(0) + (15 kg)(3.0 m/s) = (40.0 kg + 15 kg) v$$ $$v = 0.8 m/s$$