Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 5 - Plug and Chug: 26

Answer

$v=215 \frac{km}{h}$

Work Step by Step

The parallelogram rule is discussed on pages 28-29, and relative velocity is discussed on page 51. The plane's velocity relative to the ground equals the vector sum of its velocity relative to the air, and the air's velocity relative to the ground. The two velocities are perpendicular. Find the resultant of the perpendicular 200 km/h and 80 km/h vectors by using the Pythagorean theorem. $$(200 \frac{km}{h})^{2}+(80 \frac{km}{h})^{2} =v^{2}$$ $$v=215 \frac{km}{h} $$
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