#### Answer

The 70-foot bus is measured to be slightly less than 1 foot long when it is moving at 99.99 percent of c.

#### Work Step by Step

Let $L_{o}$ represent the original, rest length of the bus, and L the measured length of the moving object.
$$L = L_{o} \sqrt{1-\frac{ v^{2} } { c^{2} }} $$
$$L = (70 feet) \sqrt{1-0.9999^{2}} = 0.99 feet $$
This is discussed on page 676.
Alternatively, find $\gamma$ at v = 0.9999c. It is $\frac{1}{\sqrt{1-v^{2}/c^{2}}}$, or $\frac{1}{\sqrt{1-0.9999^{2}}}$, which is 70.7.
The factor $\gamma$ is the length contraction factor. Divide 70 feet by $\gamma$ to find the contracted length.