## Conceptual Physics (12th Edition)

A meterstick moving at $99.5\%$ the speed of light would appear to be one-tenth its original length.
Let $L_{o}$ represent the original, proper length, and L the measured length of the moving object. $$L = L_{o} \sqrt{1-\frac{ v^{2} } { c^{2} }}$$ $$L = L_{o} \sqrt{1-0.995^{2}} = \frac{1}{10} L_{o}$$ This is discussed on page 676.