Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 33 - Think and Explain: 62

Answer

90 cpm. 40 cpm.

Work Step by Step

At 2 m, double the distance, the count rate is $\frac{1}{2^{2}} = \frac{1}{4}$ of 360 counts/minute, or 90 cpm. At 3 m, triple the distance, the count rate is $\frac{1}{3^{2}} = \frac{1}{9}$ of 360 counts/minute, or 40 cpm.
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