## Conceptual Physics (12th Edition)

From page 46, using g =$10 \frac{m}{s^{2}}$, v = gt = 100 m/s. Averaging the initial velocity of zero with the final velocity of 100 m/s, we obtain 50 m/s, downward. We can find how far it drops by multiplying the average velocity and the time. $$d = (50 \frac{m}{s})(10 s) = 500 m$$ Alternatively, we could use an equation from page 48, $d = \frac{1}{2}gt^{2}$. Both approaches give the same answer.