## Conceptual Physics (12th Edition)

Published by Addison-Wesley

# Chapter 3 - Reading Check Questions (Comprehension): 21

#### Answer

For an object starting at rest, the distance fallen in 1 second is 5 m. After 4 seconds, it will have fallen a distance of 80 m.

#### Work Step by Step

This is discussed on page 48. $$d_{1}=\frac{1}{2}gt^{2}=\frac{1}{2}\times10m/s^{2}\times(1 s)^{2}=5 m$$ $$d_{2}=\frac{1}{2}gt^{2}=\frac{1}{2}\times10m/s^{2}\times(4 s)^{2}=80 m$$

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