Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 22 - Think and Solve: 42

Answer

$2 \times 10^{8} J$.

Work Step by Step

The electric PE, as shown on page 422, is charge multiplied by electric potential. $$PE = qV = (2 C)(100 \times 10^{6} V) = 2 \times 10^{8} J$$
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