Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 22 - Think and Solve: 37

Answer

$q = 2.8 \times 10^{-6} C$

Work Step by Step

Use Coulomb's Law, $F = k \frac{q_{1} \; q_{2}}{d^{2}}$. $$20 N = 9.0 \times 10^{9} \frac{N m^{2}}{C^{2}} \frac{q^{2}}{(0.06 m)^{2}}$$ $$q^{2} = 8.0 \times 10^{-12} C^{2}$$ $$q = 2.8 \times 10^{-6} C$$
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