Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 22 - Think and Explain: 66

Answer

The force is reduced to 1/4 of its original value, no matter the sign of the original charges. Coulomb’s law defends our answer.

Work Step by Step

Use Coulomb's Law. $$F = k \frac{q_{1} \; q_{2}}{d^{2}}$$ If d is doubled, the force is divided by a factor of 4. This statement does not depend on the value or signs of the charges q.
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