## Conceptual Physics (12th Edition)

$\Delta T = 17.8^{\circ}C$.
Calculate the work that the hammer does on the nail. $$F \times d = (600 N)(0.08 m) = 48 J$$ This energy input raises the temperature of the nail, and the change can be found from $Q = cm\Delta T$. $$48 J = (450 J/(kg^{\circ} C))(0.006 kg)(\Delta T)$$ Solve to get $\Delta T = 17.8^{\circ}C$.