Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 16 - Plug and Chug: 34

Answer

$$Q = cm \Delta T$$ $$=\frac{1 cal}{g \cdot ^{\circ}C}(50 g)(100^{\circ}C - 0^{\circ}C ) = 5000 cal$$
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