Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 15 - Think and Solve: 37

Answer

Calculate the required heat. $$Q = cm \Delta T$$ $$=\frac{1 cal}{g \cdot ^{\circ}C}(50000 g)(20^{\circ}C ) = 1000000 cal = 1000 kcal$$ Now convert to joules. $$1000000 cal \frac{4.19 J}{1 cal} = 4190 kJ$$

Work Step by Step

The conversion factor is on page 289.
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