# Chapter 15 - Plug and Chug: 34

The book asks us to show that 12570 J are required to raise the temperature of 0.30 kg of water from $22^{\circ}C$ to $30^{\circ}C$ . There is a typo; the answer is actually 10056 J.

#### Work Step by Step

$$Q = cm \Delta T$$ $$=\frac{4190 J}{kg \cdot ^{\circ}C}(0.30 kg)(30^{\circ}C - 22^{\circ}C ) = 10056 J$$

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