Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 15 - Plug and Chug: 33

Answer

The book asks us to show that 3000 cal are required to raise the temperature of 300 g of water from $22^{\circ}C$ to $30^{\circ}C$ . There is a typo; the answer is actually 2400 calories.

Work Step by Step

$$Q = cm \Delta T$$ $$=\frac{1 cal}{g \cdot ^{\circ}C}(300 g)(30^{\circ}C - 22^{\circ}C ) = 2400 cal$$
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