## Conceptual Physics (12th Edition)

V = $0.1 m^{3}$
Her density must be about the same as that of water, $1000 \frac{kg}{m^{3}}$. Density = $1000 \frac{kg}{m^{3}} = \frac{100 kg}{V}$, solve for V = $0.1 m^{3}$. This is discussed on page 251.