## Conceptual Physics (12th Edition)

Published by Addison-Wesley

# Chapter 13 - Think and Solve: 45

#### Answer

V = $0.1 m^{3}$

#### Work Step by Step

Her density must be about the same as that of water, $1000 \frac{kg}{m^{3}}$. Density = $1000 \frac{kg}{m^{3}} = \frac{100 kg}{V}$, solve for V = $0.1 m^{3}$. This is discussed on page 251.

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