Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 12 - Think and Solve: 33

Answer

2 cm. 4 cm each for a total of 8 cm.

Work Step by Step

Hooke’s law says that the stretch is proportional to the applied force, $F \sim \Delta x$. In Case a, each spring supports only 5 N, half the weight. Each spring stretches half as far as before, or 2 cm. In Case b, each spring still supports 10 N. Each spring stretches 4 cm, so the weight is lowered by a total distance of 8 cm. This is discussed on page 231.
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