# Chapter 12 - Think and Solve: 32

10 cm.

#### Work Step by Step

Hooke’s law says that the stretch is proportional to the applied force, $F \sim \Delta x$. The new force, 50 N, is $\frac{5}{3}$ of the old, 30 N. The spring will now stretch $\frac{5}{3}$ times as far, or 10 cm. This is discussed on page 231.

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