# Chapter 10 - Think and Solve: 27

a. Use the time of 30 seconds. As far as vertical motion is concerned, the engine started from rest. We need only find the height from which it takes 30 s to hit the ground. $$y = \frac{1}{2}g t^{2} = 5 \frac{m}{s^{2}}(30 s)^{2} = 4500 m$$ This is discussed on page 48. b. The horizontal velocity of the engine does not change. Find the horizontal distance it moved in the 30-s drop time. $$d = vt = (280 \frac{m}{s})(30 s) = 8400 m$$ c. The plane would have traveled the same horizontal distance, so in the absence of air resistance, the fallen engine lands directly below the airplane.

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