Conceptual Physics (12th Edition)

Published by Addison-Wesley
ISBN 10: 0321909100
ISBN 13: 978-0-32190-910-7

Chapter 10 - Reading Check Questions (Comprehension): 7

Answer

$20^{\circ}$.

Work Step by Step

The question says that a projectile is launched upward at $70^{\circ}$, and asks for the other angle of launch that will produce the same range, for the same launch speed. The answer in the back of the book says $15^{\circ}$ and refers you to Figure 10.11. Unfortunately, Figure 10.11 shows that $15^{\circ}$ produces the same range as $75^{\circ}$, not as $70^{\circ}$. Since the figure in the book doesn't help answer the question for an initial angle of $70^{\circ}$, we turn to other resources. Equations in other texts or found via your favorite search engine (try "range equation") show that the range can be written as $R = \frac{(v_{initial})^{2}sin(2 \theta)}{g}$. An initial angle of $70^{\circ}$ or $20^{\circ}$ gives the same range.
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