Answer
a) The net force acting on 2.0 kg ball: F=mg= $2.0\,kg\times9.8m/s^{2}=20.\,N$
On 6.0 kg ball: F= $6.0kg\times9.8m/s^{2}=59\,N$
b) a in free fall is same for both equal to $9.8 m/s^{2}$
Work Step by Step
See the answer above.
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 134: 5
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