Answer
The picture is attached below.
Work Step by Step
Hex-1-yne, when reacted with two $H-Br$ forms 2,2-dibromohexane. 2,2-dibromo means the presence of two bromine atoms at carbon number 2.
The triple bond in hex-1-yne found between carbon number 1 and carbon number 2 breaks, and the bond between $H-Br$ also breaks. H and Br atoms attach with these carbons and form a single bond with this carbon. Bromine attaches to carbon number 2 whereas Hydrogen forms a bond with carbon number 1. In this way, the triple bond is converted into a double bond.
Furthermore, when the above product is reacted with the second $H-Br$, the double bond between the carbon atoms breaks. H and Br atoms attach with these carbons and form a single bond with this carbon. Bromine attaches to carbon number 2 whereas Hydrogen forms a bond with carbon number 1. In this way, the double bond is converted into a single bond and hence, 2,2-dibromohexane is formed.
