Answer
The picture is attached below.
Work Step by Step
Hex-1-yne, when reacted with $H_{2}$ and $HBr$, forms 2-bromohexane. 2-bromo means the presence of one bromine atom at carbon number 2.
The triple bond in hex-1-yne found between carbon number 1 and carbon number 2 breaks, and the bond between $H-H$ also breaks in the presence of lindlar's catalyst. $H$ atoms attach with these carbons and form a single bond with carbon number 1 and carbon number 2. In this way, the triple bond is converted into a double bond.
Furthermore, when the above formed product is reacted with $H-Br$, the double bond between the carbon atoms breaks. H and Br atoms attach with these carbons and form a single bond with this carbon. Bromine attaches to carbon number 2 whereas Hydrogen forms a bond with carbon number 1. In this way, the double bond is converted into a single bond and hence, 2-bromohexane is formed.
