Answer
The picture is attached below.
Work Step by Step
Hex-1-yne, when reacted with $Cl_{2}$, forms 1,2-dichlorohex-1-ene. 1,2-dichloro means the presence of two chlorine at carbon number 1 and carbon number 2.
The triple bond in hex-1-yne found between carbon number 1 and carbon number 2 breaks. Similarly, the bond between the chlorine molecules also breaks. These Chlorine atoms attach with these carbons and forms a single bond with this Carbon. In this way, the triple bond is converted into a double bond. (ene means the presence of a double bond.) The product has E and Z isomers.
