Answer
With $H−C≡C-H$ (acetylene) 1) $NaNH_2$ 2) $CH_3CH_2CH_2CH_2Br$ can be used to synthesize the following product.
Work Step by Step
1) $NaNH_2$ deprotonates $H−C≡C-H$ and forms $H−C≡C:^-$. This attacks the 2) $CH_3CH_2CH_2CH_2Br$ to give the product.
