## Organic Chemistry (8th Edition)

The products are $H-C≡C-Na^+$ and $:NH_2$
As there is an acetylenic proton there will be a reaction. One of the hydrogen gets reduced by sodium metal to give Na salt of the amide ion, a very strong conjugate base. And the amide ion is the conjugate base of ammonia so it is very strong. As a result, the reaction forms $H-C≡C-Na^+$ and $:NH_2$