Answer
Two different products are formed. The proposed reaction is shown in the picture.
Work Step by Step
For the first product the mechanism is-
Step 1: Protonation of the pi bond forms a carbocation.
Step 2: Attack by the chloride ion gives the addition product.
For the second product the mechanism is-
Step 1: Protonation of the pi bond forms a carbocation.
Step 2: The Ethanol attacks on the carboncation, then another ethanol deprotonates the ethanol, forming the second product.
So there is a formation of a mixture of two products.
