Answer
The major product is shown in the picture. It is 1-methyl-1,2-cyclohexanediol.
Work Step by Step
The reagent $CH_3CO_3H$ forms an epoxide across the double bond. The $H^+$ protonates the epoxide. Then the water molecule comes and attacks on the most substituted carbon. One of the H on the water molecule is deprotonated and then it forms an OH group. The OH groups are added anti.