Answer
The product formed in this reaction is 2-phenyl-2-propanol.
Work Step by Step
Draw the structures first and locate the double bond. The product formed is 2-phenyl-2-propanol.
Steps:
1) Protonation of the double bond forms a carbocation.
2) Nucleophilic attack by water on the most substituted carbon gives a protonated alcohol.
3) Deprotonation gives the alcohol.
