Answer
The compound has 3 geometric isomers. The structures are drawn and labeled in the attached image.
Work Step by Step
The compound has 3 geometric isomers:
$(1E,5E)-cyclodeca-1,5-diene$
$(1Z,5E)-cyclodeca-1,5-diene$
$(1Z,5Z)-cyclodeca-1,5-diene$
The structures are drawn and labeled in the attached image.