Answer
The IUPAC name of the compound is $4,4-dichloro-5-cyclopropyl-1-iodoheptane.$
Work Step by Step
The compound has 7 carbon atoms in its longest carbon chain ($hept-$). It has 2 $chloro$ groups at position 4, a $cyclopropyl$ group at position 5 and an $iodo$ group at position 1. So, the IUPAC name of the compound is $4,4-dichloro-5-cyclopropyl-1-iodoheptane.$