Answer
$[α]_{D^{25}} = +8.7^{\circ}$
Work Step by Step
We know,
$2.0g/10mL = 0.20g/mL$
$100mm = 1dm$
So,
$[α]_{D^{25}} = \frac{+1.74^{\circ}}{(0.20)(1)} = +8.7^{\circ} $ for (+)-glyceraldehyde.
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