Answer
The IUPAC name of the compound is $trans−1,4−dimethylcyclohexane$
Work Step by Step
The compound has 6 carbon atoms in the carbon ring ($−hex$). There are 2 methyl groups attached to the ring at positons 1 and 4, both on the oppposite side of the plane relative to the H atoms ($trans$). So, the IUPAC name of the compound is $trans−1,4−dimethylcyclohexane$