Answer
The IUPAC name of the compound is $trans−1,2−dimethylcyclohexane$
Work Step by Step
The compound has 6 carbon atoms in the carbon ring ($−hex$). There are 2 methyl groups attatched to the ring at poisitons 1 and 2, both on the oppsoite side of the plane relative to the $H$ atoms ($trans$). So, the IUPAC name of the compound is $trans−1,2−dimethylcyclohexane$