Answer
The IUPAC name of the compound is $cis−1,3−dimethylcyclohexane$
Work Step by Step
The compound has 6 carbon atoms in the carbon ring ($−hex$). There are 2 methyl groups attatched to the ring at poisitons 1 and 3, both on the same side of the plane relative to the $H$ atoms ($cis$). So, the IUPAC name of the compound is $cis−1,3−dimethylcyclohexane$
