## Organic Chemistry (8th Edition)

Published by Pearson

# Chapter 2 - Structure and Properties of Organic Molecules - Problems: Problem 2-4

#### Answer

$C_1$ hybridization: $sp^3$ geometry: tetrahedral bond angles: 109.5° $C_2$ hybridization: $sp$ geometry: linear bond angles: 180° $N$ hybridization: $sp$ geometry: linear bond angles: 180°

#### Work Step by Step

The $C_1$ has four domains (four single bonds). The hybridization is $sp^3$ .The geometry is tetrahedral and the bond angle is 109.5° The $C_2$ has two domains (one single bond and one triple bond). The hybridization is $sp$. The geometry is linear and the bond angle is 180° The $N$ has two domains (one triple bond and one lone pair). The hybridization is $sp$. The geometry is linear and the bond angle is 180°

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