Answer
Antiaromatic
Work Step by Step
For compounds to be aromatic they have to pass three tests:
1) Planar- if not planar then they are non- aromatic
2) Hybridization- should be sp/sp$^2$
3) Huckle's rule- for aromatic 4n+2= # pi electrons (should be a whole number when solved)
and for Anti-aromatic 4n = # pi electrons (should be a whole number when solved)
It is planar so it passes the 1st test. It has no $sp^3$ carbons so it passes the 2nd test. There are 8 pi electron which is 4n and not a huckel number. Thus, it is antiaromatic.
