Organic Chemistry (8th Edition)

Published by Pearson
ISBN 10: 0321768418
ISBN 13: 978-0-32176-841-4

Chapter 10 - Structure and Synthesis of Alcohols - Problems: Problem 10-1 b

Answer

(E)-5-bromohept-3-en-2-ol

Work Step by Step

1. Find the longest carbon chain with -OH and number it giving -OH the least number. 2. Locate the Br which would be Bromo in the name. 3. Locate the double bond which would be 3. 4. Write the name by dropping e from the name of the longest chain and end with an -ol. 5. It's E because the highest priority groups like on different sides of the double bond. Since bromine is at the 5th carbon after numbering the chain from left to right, it will be 5-bromo. The double bond is at 3 so hept-3-en and since alcohol is at 2, it will be -2-ol.
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