## Organic Chemistry (8th Edition)

Draw a carbon wherever two lines meet and, a line begins and ends. And then add the number of hydrogens so that each carbon has four bonds. The molecular formula is $C_8H_{16}O$.
1) Draw a carbon wherever two lines meet and, a line begins and ends. 2) Draw O where O is given and two lone pairs on O. 3) Then add the number of hydrogens so that each carbon has four bonds. 4) Count the number of C, H and O. In this structure there are 8 Carbons, 16 hydrogens and 1 Oxygen. Thus, the molecular formula is $C_8H_{16}O$.