Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 8 - Quantities in Chemical Reactions - Exercises - Problems - Page 279: 72

Answer

(a) 125 kJ (b) 188 kJ (c) 125 kJ (d) 208 kJ

Work Step by Step

Based on the given data, we can write Heat $=\frac{-125\,kJ}{2\,mol\,A}=\frac{-62.5\,kJ}{1\,mol\,A}=\frac{-62.5\times3\,kJ}{3\,mol\,A}=\frac{-125\,kJ}{3\,mol\,B }=\frac{-41.667\,kJ}{1\,mol\,B}=\frac{-41.667\times5\,kJ}{5\,mol\,B}$ Negative sign indicates that the heat is emitted. (a) When 2 mol A reacts completely, 125 kJ heat is emitted. (b) When 3 mol A reacts completely, $62.5\times3=188$ kJ heat is emitted. (c) When 3 mol B reacts completely, 125 kJ heat is emitted. (d) When 5 mol B reacts completely, $41.667\times5=208$ kJ heat is emitted.
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