Answer
3 mol A, 0 mol B, 4 mol C.
Work Step by Step
Calculating how much product can be made based on the amount of each reactant, we have
$9\,mol\,A\times\frac{2\,mol\,C}{3\,mol\,A}=6\,mol\,C$
$8\,mol\,B\times\frac{2\,mol\,C}{4\,mol\,B}=4\,mol\,C$
Since $8\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Therefore, moles of B after the reaction= 0.
Now, 3 moles of A react completely with 4 moles of B.
$\implies $ 6 moles of A react with 8 moles of B.
So, after the reaction, moles of A=$9-6=3$
Moles of C= theoretical yield (maximum amount of product that can be made in the reaction based on the amount of limiting reactant)= $4\,mol$
