Answer
(a) $1\,mol\,TiCl_{4}$
(b) $4.5\,mol\,TiCl_{4}$
(c) $0.456\,mol\,TiCl_{4}$
(d) $7.9\,mol\,TiCl_{4}$
Work Step by Step
(a) Calculating how much product can be made based on the amount of each reactant, we have
$2\,mol\,Ti\times\frac{1\,mol\,TiCl_{4}}{1\,mol\,Ti}=2\,mol\,TiCl_{4}$
$2\,mol\,Cl_{2}\times\frac{1\,mol\,TiCl_{4}}{2\,mol\,Cl_{2}}=1\,mol\,TiCl_{4}$
Since $2\,mol\,Cl_{2}$ makes the least amount of product, it is the limiting reactant.
Theoretical yield is the maximum amount of product that can be made in a reaction based on the amount of limiting reactant.
Therefore, theoretical yield= $1\,mol\,TiCl_{4}$.
(b) Calculating how much product can be made based on the amount of each reactant, we have
$5\,mol\,Ti\times\frac{1\,mol\,TiCl_{4}}{1\,mol\,Ti}=5\,mol\,TiCl_{4}$
$9\,mol\,Cl_{2}\times\frac{1\,mol\,TiCl_{4}}{2\,mol\,Cl_{2}}=4.5\,mol\,TiCl_{4}$
Since $9\,mol\,Cl_{2}$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $4.5\,mol\,TiCl_{4}$
(c) Calculating how much product can be made based on the amount of each reactant, we have
$0.483\,mol\,Ti\times\frac{1\,mol\,TiCl_{4}}{1\,mol\,Ti}=0.483\,mol\,TiCl_{4}$
$0.911\,mol\,Cl_{2}\times\frac{1\,mol\,TiCl_{4}}{2\,mol\,Cl_{2}}=0.456\,mol\,TiCl_{4}$
Since $0.911\,mol\,Cl_{2}$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $0.456\,mol\,TiCl_{4}$
(d) Calculating how much product can be made based on the amount of each reactant, we have
$12.4\,mol\,Ti\times\frac{1\,mol\,TiCl_{4}}{1\,mol\,Ti}=12.4\,mol\,TiCl_{4}$
$15.8\,mol\,Cl_{2}\times\frac{1\,mol\,TiCl_{4}}{2\,mol\,Cl_{2}}=7.9\,mol\,TiCl_{4}$
Since $15.8\,mol\,Cl_{2}$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $7.9\,mol\,TiCl_{4}$
