Answer
(a) $1\,mol\,K$
(b) $1.8\,mol\,K$
(c) $1\,mol\,Cl_{2}$
(d) $14.6\,mol\,K$
Work Step by Step
(a) Calculating how much product can be made based on the amount of each reactant, we have
$1\,mol\,K\times\frac{2\,mol\,KCl}{2\,mol\,K}=1\,mol\,KCl$
$1\,mol\,Cl_{2}\times\frac{2\,mol\,KCl}{1\,mol\,Cl_{2}}=2\,mol\,KCl$
Since $1\,mol\,K$ makes the least amount of product, it is the limiting reactant.
(b) Calculating how much product can be made based on the amount of each reactant, we have
$1.8\,mol\,K\times\frac{2\,mol\,KCl}{2\,mol\,K}=1.8\,mol\,KCl$
$1\,mol\,Cl_{2}\times\frac{2\,mol\,KCl}{1\,mol\,Cl_{2}}=2\,mol\,KCl$
Since $1.8\,mol\,K$ makes the least amount of product, it is the limiting reactant.
(c) Calculating how much product can be made based on the amount of each reactant, we have
$2.2\,mol\,K\times\frac{2\,mol\,KCl}{2\,mol\,K}=2.2\,mol\,KCl$
$1\,mol\,Cl_{2}\times\frac{2\,mol\,KCl}{1\,mol\,Cl_{2}}=2\,mol\,KCl$
Since $1\,mol\,Cl_{2}$ makes the least amount of product, it is the limiting reactant.
(d) Calculating how much product can be made based on the amount of each reactant, we have
$14.6\,mol\,K\times\frac{2\,mol\,KCl}{2\,mol\,K}=14.6\,mol\,KCl$
$7.8\,mol\,Cl_{2}\times\frac{2\,mol\,KCl}{1\,mol\,Cl_{2}}=15.6\,mol\,KCl$
Since $14.6\,mol\,K$ makes the least amount of product, it is the limiting reactant.