Answer
(a) 14 mol $CO_{2}$, 18 mol $H_{2}O$
(b) 2.8 mol $CO_{2}$, 3.7 mol $H_{2}O$
(c) 0.167 mol $CO_{2}$, 0.223 mol $H_{2}O$
(d) 0.0335 mol $CO_{2}$, 0.0446 mol $H_{2}O$
Work Step by Step
(a) $4.6\,mol\,C_{3}H_{8}\times\frac{3\,mol\,CO_{2}}{1\,mol\,C_{3}H_{8}}=14\,mol\,CO_{2}$
$4.6\,mol\,C_{3}H_{8}\times\frac{4\,mol\,H_{2}O}{1\,mol\,C_{3}H_{8}}=18\,mol\,H_{2}O$
(b) $4.6\,mol\,O_{2}\times\frac{3\,mol\,CO_{2}}{5\,mol\,O_{2}}=2.8\,mol\,CO_{2}$
$4.6\,mol\,O_{2}\times\frac{4\,mol\,H_{2}O}{5\,mol\,O_{2}}=3.7\,mol\,H_{2}O$
(c) $0.0558\,mol\,C_{3}H_{8}\times\frac{3\,mol\,CO_{2}}{1\,mol\,C_{3}H_{8}}=0.167\,mol\,CO_{2}$
$0.0558\,mol\,C_{3}H_{8}\times\frac{4\,mol\,H_{2}O}{1\,mol\,C_{3}H_{8}}=0.223\,mol\,H_{2}O$
(d) $0.0558\,mol\,O_{2}\times\frac{3\,mol\,CO_{2}}{5\,mol\,O_{2}}=0.0335\,mol\,CO_{2}$
$0.0558\,mol\,O_{2}\times\frac{4\,mol\,H_{2}O}{5\,mol\,O_{2}}=0.0446\,mol\,H_{2}O$
