Answer
a) $7.067 moles NH_{3} $
b) $3.04 moles NH_{3} $
c) $0.0773 moles NH_{3} $
d) $1.30\times10^{8} moles NH_{3} $
Work Step by Step
We can solve this by looking at the balanced chemical equation and using the mole ratios:
$3N_{2}H_{4} --> 4NH_{3} + N_{2}$
a) $5.3 moles N_{2}H_{4} \times\frac{4 moles NH_{3}}{3N_{2}H_{4}} = 7.067 moles NH_{3} $
b) $2.28 moles N_{2}H_{4} \times\frac{4 moles NH_{3}}{3N_{2}H_{4}} = 3.04 moles NH_{3} $
c) $0.058 moles N_{2}H_{4} \times\frac{4 moles NH_{3}}{3N_{2}H_{4}} = 0.0773 moles NH_{3} $
d) $9.76\times10^{7} moles N_{2}H_{4} \times\frac{4 moles NH_{3}}{3N_{2}H_{4}} = 1.30\times10^{8} moles NH_{3} $
