Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 6 - Chemical Composition - Exercises - Problems - Page 199: 59

Answer

$5.4$ moles of Chlorine (Cl)

Work Step by Step

We can figure this out using simple mole ratios. According to the formula $CaCl_{2}$, 1 mole of $CaCl_{2}$ contains two moles of Cl. So, 2.7 moles of $CaCl_{2}$ contains $5.4$ moles of Cl. $2.7 moles\times 2 = 5.4 moles$
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