Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 5 - Molecules and Compounds - Exercises - Problems - Page 157: 31

Answer

The formula would be NI$_3$ as there are 3 iodines for every nitrogen.

Work Step by Step

Nitrogen is further left on the table than is iodine, hence it is put first.
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